if a force of 10 Newton acts on a surfaces of areas in the ratio 1 : 2 the thrust,has what ratio
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Hey mate.....☺☺☺
Here is your answer⤵⤵⤵⤵
⏩We know that,
➡Thrust on first surface = Force / Area
= 10/x
➡Thrust on second surface = Force / Area
=10/2x
Therefore, required ratio= 10/x × 2x/10 =2:1
❤❤Hope it will help you❤❤
❤❤❤Thanks❤❤❤
✌✌✌✌
Here is your answer⤵⤵⤵⤵
⏩We know that,
➡Thrust on first surface = Force / Area
= 10/x
➡Thrust on second surface = Force / Area
=10/2x
Therefore, required ratio= 10/x × 2x/10 =2:1
❤❤Hope it will help you❤❤
❤❤❤Thanks❤❤❤
✌✌✌✌
subeshkumarjha107:
you made it simple thankyou
hey but this is wrong answer.I got that
1:1
it is right
pressure= thrust / area
thrust= pressure × area
thrust= force / area ×area. then put their values
You wrote. thrust =force / area
anyway thanks
Answered by
0
Answer:
2:1 is the answer
I HOPE THIS ANSWER WILL HELP'S YOU
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