Question

If a force of 10 Newton is applied on a body and another force is applied at 60 degree their resultant is 20 Newton find the value of second force

Answer 1

Answer:- -5+5√3. And. -5+√3

Explanation:

Force A=10 N. Force B=?

Resultant=20 N. α=60'=1/2

R^2=A^2+B^2+2ABcos60

200=100+B^2+10B

0=B^2+B-100

Using quad. Formula

[-B+-(√B^2-4AC)]/2A

B=(-10+-10√3)/2

=-5+-5√3