Question

If a force of 10N acts on a body of mass 2kg,
initially moving with 2m/s. Find the velocity at the
end of 5 seconds​

Answer 1

Explanation:

force= mass × acceleration

10N=2kg x a

a= 5m/s^2

According to first equation of motion,

v=u+at

v=2+5×5

v=2+10

v=12m/s

Hence, final velocity is 12 m/s.

Answer 2

Answer :

Magnitude of applied force = 10N

Mass of body = 2kg

Initial velocity = 2m/s

We have to find final velocity of body after 5 seconds$.$

★ As per newton's second law of motion, force is measured as the rate of change of linear momentum.

• F = m(v - u)/t

F denotes force

m denotes mass

v denotes final velocity

u denotes initial velocity

t denotes time

➙ F = m(v - u)/t

➙ 10 = 2(v - 2)/5

➙ v - 2 = 50/2

➙ v = 25 + 2

➙ v = 27m/s

Cheers!