Question

If a force of 12 N acting on a body changes its velocity uniformly from 2 m/s to 5 m/s in 20 s then what is the mass of the body? A. 40 kg B. 48 kg C. 80 kg D. 96 kg​.

Gm ​

Answer 1

Question :-

✯ If a force of 12 N acting on a body changes its velocity uniformly from 2 m/s to 5 m/s in 20 s then what is the mass of the body?

Given :-

✯ If a force of 12 N acting on a body changes its velocity uniformly from 2 m/s to 5 m/s in 20 s.

Find Out :-

✯ Then what is the mass of the body?

Solution :-

We have :

Force = 12 N

Initial velocity u = 2 m/s

Final velocity v = 5 m/s

Time = 20 s

✭ In case of acceleration :-

As we know that :

☆ \red{ \boxed{\sf{v =\: u + at}}}v=u+at ☆

So, according to the question or ATQ :-

\leadsto \sf 5 =\: 2 + a(20)⇝5=2+a(20)

\leadsto \sf 5 - 2 =\: 20a⇝5−2=20a

\leadsto \sf 3 =\: 20a⇝3=20a

\leadsto \sf \dfrac{3}{20} =\: a⇝203=a

\leadsto \sf\boxed{\bold{\red{a =\: \dfrac{3}{20}\: m/s^2}}}⇝a=203m/s2

✭ In case of mass :-

As we know that :

★ \red{ \boxed{\sf{F =\: ma}}}F=ma ★

So, according to the question or ATQ :-

\leadsto \sf 12 =\: m \times \dfrac{3}{20}⇝12=m×203

\leadsto \sf \dfrac{12}{\dfrac{3}{20}} =\: m⇝20312=m

\leadsto \sf \dfrac{12}{1} \times \dfrac{20}{3} =\: m⇝112×320=m

\leadsto \sf \dfrac{240}{3} =\: m⇝3240=m

\leadsto⇝ {\small{\bold{\purple{\underline{m =\: 80\: kg}}}}}m=80kg

Henceforth, the mass of the body is 80 kg.

Correct options is C) 80 kg .

Answer 2

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