Question

if a force of 15N is applied at an angle of 60 degree, find moment of this force about the the point degree.

Answer 1

Answer:

moment of force = f ×displacement angle

which is equal =15 N × 60

=> 900

Answer 2

Answer:

Moment of force about a point is $\frac{15}{2} r$

Explanation:

Given applied force,  $F= 15N$

          angle, $\theta=60^{o}$

Moment of force about a point is defined as the product of force applied and the perpendicular distance between the force and point.

                  i.e., $\vec M=\vec F\times \vec r$  

                        $\vec M=\vec F \times rcos\theta$

                             $=15 \times r\times cos60^{o}$

                             $=15 \times r\times \frac{1}{2}$

                             $=\frac{15}{2} r$

Moment of force about a point is $\frac{15}{2} r$.