Question

If a force of 20N act on a rigid body such that perpendicular distance between line of action of force and fived point is 10 m calculate moment of force?​

Answer 1

Answer :-

The moment of force is 200Nm.

Step-by-step explanation :

Given that,

• Force applied on a rigid body = 20N
• Perpendicular distance between line of force and turning point = 10m

Therefore,

Moment of force (M) = ?

Force applied (F) = 20N

Perpendicular distance (d) = 10m

We know,

M = F × d,

Where,

• M = moment of force
• F = Force applied
• d = perpendicular distance.

⇒ M = F × d

⇒ M = 20N × 10m

⇒ M = 200 Nm.

Hence, The moment of force is 200Nm.

Answer 2

Answer:-

• Force=20N
• Perpendicular distance=10m

We know

$\boxed{\sf Moment\:of\:force=Force\times Perpendicular\:Distance}$

$\\ \sf\longmapsto Moment\:of\:Force=20N\times 10m$

$\\ \sf\longmapsto Moment\:of\:Force=200Nm$