Question

if a force of 250 N act on body , of mass 30kg velocity is 50ms_1 what will be the distance of the body?

Answer 1

Given :-

Force acting on body = F = 250 N

Mass of body = m = 30 Kg

Velocity of body = 50 ms-¹

F = ma

250 = 30a

a = 25/3 ms-²

Now, using third equation of Motion,

v² - u² = 2as

(50)² = 2 × 25/3 × S

50 × 50 = 50/3 × S

S = 150 m

Hence,

Distance travelled = S = 150 m.

Answer 2

$\boxed{\rm{\orange{Question \longrightarrow }}}$

if a force of 250 N act on body , of mass 30kg velocity is 50m/s what will be the distance of the body?

$\boxed{\rm{\blue{Find\longrightarrow }}}$

• Distance ??

$\boxed{\rm{\red{Given \longrightarrow }}}$

$\rm{Force [F] = 250N}$

$\rm{ Velocity [v] = 50m/s}$

$\rm{Mass [m] = 30kg}$

$\boxed{\rm{\orange{SoLution \longrightarrow }}}$

According to newton's second law of motion,

$\boxed{\sf{F=ma}}$

Put value in this formula we will find the value of a(acceleration),

$\sf{250 = 30\times a}$

$\bf{\therefore a= 8.33m/s^2}$

Now,

by using third equation of motion,

$\boxed{\sf{v^2-u^2= 2as}}$

Put value in the formula, we get

$\sf{50^2 - 0^2 = 2\times 8.33 \times s}$

$\sf{s= \dfrac{2500}{16.66} = 150.06m}$

$\boxed{\bf{\pink{ \bigstar \therefore Distance =150.06m \bigstar }}}$

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