*If a force of 5 N is applied on a block of mass 10
kg and the block remains at rest, then the
magnitude and the direction of friction is
(1) 10 N normal to the direction of motion
(2) 5 N along the direction of applied force
(3) 5 N opposite to the direction of applied force
(4) 10 N opposite to the direction of applied force
Answers
Answered by
1
Answer:
Answer:20N
Explanation: this is because one side it is 80 and other is 100 so the force will be 20 N on the other side
Answered by
2
Answer:
Explanation:
Answer- (3) 5N opposite to the direction of the applied force.
This is because as the acceleration is 0 the force of friction = force applied. It is a case of static friction. Moreover friction always act opposite to the direction of the applied force. So coorect answer is (3)
Similar questions