Question

If a force of 50N is applied to the body
on the right side while a force of 20N is applied to
the body on the left side and initially body is at rest.
What is the behaviour of the motion of the body?

Answer 1

Explanation:

Retarding force, F=50N

Mass of the body, m=20kg

Initial velocity of the body, u=15m/s

Final velocity of the body, v=0

Using Newtons second law of motion, the acceleration (a) produced is given by:

F=ma

50=20 ×a

a=−50/20=−2.5m/s

2

Using the first equation of motion, the time (t) taken by the body to come at rest

v=u+at

t=−u/a=−15/−2.5=6s

Answer 2

Answer:

when applying motion, firstly the body moves towards right.. Then the body suddenly goes to rest..

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