Question

If a force of 5Nacts on a body it accelarates 10 m/s therefore when it accelarates 20 m/s how much force is acting on it ?

Answer 1

First method :

Consider the first part of the question as case 1

so we get

Force = 5N

Acceleration = 10m/s^2

By using

F= ma ( Force = mass X acceleration )

we can find mass

Mass = Force/acceleration

so , we get

M = 5N/10m/s^2

= 0.5 Kg

so here the mass of the body is 0.5 kg

Now coming to the next part of the question it is given the body possess acceleration of 20m/s^2

so as we know the mass of the body

we can find the force acting on it using the above formula

F=ma ( Force = mass X acceleration)

so,

Force = 0.5 X 20

= 5/10 X 20

= 5 X 2

= 10

Second method:

Here for 10 m/s^2 of acceleration 5N of force is acting.

similarly if the acceleration becomes twice then force also becomes twice

That is

10 N force Will be acting on it

Answer 2

Explanation:

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Given:

Initial velocity (u) = 0m/s

time taken = 3.0 seconds

Acceleration ( here acceleration due to gravity)

= 10 m/s^2 or 9.8m/s^2

so we have to find the distance it travelled.

Here are going to use 2nd equation of motion

s = ut + \frac{1}{2} a {t}^{2}s=ut+

2

1

at

2

\begin{gathered}s = (0)(3) + \frac{1}{2} \times 10 \times 3 \times 3 \\ s = 0 + 5 \times 9 \\ s = 0 + 45 \\ s = 45meters\end{gathered}

s=(0)(3)+

2

1

×10×3×3

s=0+5×9

s=0+45

s=45meters

So the distance travelled by the stone is 45 meters.

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