Physics, asked by Yashpede, 6 months ago

If a force of (8.0i + 2.0 j+3k) N displacas a body
through a distance of (6.01 - 3.0j-9k) m. The work
done will be
(a) 15 J
(b) 34 J
(c) 56 J
(d) 42 J

Answers

Answered by vuluvalaSubhashreddy

1

Answer:

15j

Explanation:

(8.0i + 2.0 j+3k) N× (6.0i- 3.0j-9k) m

48-6-27

48-33

15j

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