if a force of 8000 newton is applied over a vehicle of 500 kg then for how much time the velocity of the vehicle will increase from 2 metre per second to 10 metre per second also find the impulse
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F=8000N
m=500kg
u=2
v=10
t=?
F=m(v-u)/t
8000=500(10-2)/t
t=4000/8000=0.5 sec
so impulse=Ft =8000×0.5=4000N sec
m=500kg
u=2
v=10
t=?
F=m(v-u)/t
8000=500(10-2)/t
t=4000/8000=0.5 sec
so impulse=Ft =8000×0.5=4000N sec
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