If a fraction B/(3x-1) is subtracted from the fraction A/(2x+3) the resulting fraction is -11/(2x+3) (3x-1) Then find A+B.
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A/(2x+3) - B/(3x - 1) = -11/((2x +3)(3x -1))
A(3x-1) - B(2x +3) = - 11
A3x - A - B2x - 3B = 11
-A -3B = 11....(1)
3A - 2B = 0....(2)
From (1) A = -3B -11
put this value of A in (2)
-9B - 33 - 2B = 0
- 11B = 33
B = - 3
A = 9 - 11 = - 2 Ans
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