if a freely falling body covers half of its distance in the last second of the journey . find its time of fall
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Let the total distance from the ground be “h” , so the distance travelled in last one second will be “h/2”. And as always acceleration = 9.8 m/s/s (As you'll see “g” doesn't matter , it cancels out.) Also time taken to complete first half is taken as “t” and to complete second half is “t'” = 1s.
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I think the answer is 1 sec
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