If a freely falling body in the last second travels a distance equal to the distance travelled in the first three seconds what is the time of its travel?
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The distance travelled by the free falling body in 2 second is 1/2 * 10*(2)² = 20 m
that is equal to the distance traveled in last second
then, 20 m = u + 1/2*10*(1)²
or, u = 15 meter /.second
then v = u + at
or v = 15 + 10
or v = 25 m /.second
now total time is
v = u + at
25 = 0 + 5t
t = 5 second
niharika44:
How do u know that last second and acceleration is 10 sec
can u explain
acceleration due to gravity is 9.8 but is it approximately taken as 10
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