Question

If a freely floating ship has a weight of 5*10^5 N,what will be the weight of water displaced bt the ship?

Answer 1

Answer:

The weight of water displaced by the ship will be more than its own weight i.e., 5*10^5 because it is built in such a way that the weight of the water displaced by the ship is more than its weight itself. So that it will not sink in seawater.

Explanation:

DID YOU KNOW

The Titanic ship was named as the never sinking ship. But still it sank in water because of a number of factors.

1) The most common factor that everyone knows is that it was hitted by a massive iceberg because of which it got broken into two pieces.

2) The second factor that seldomly people knows is that the lower part of the ship was burnt making that portion weaker but the manager did not spread this secret.

3) Another reason was that the pilot of the ship saw the iceberg but by mistake he turned the ship to the opposite direction where the iceberg was present.

KINDLY SELECT MY ANSWER AS THE BRAINLIEST ANSWER.

Answer 2

The answer is 4.9 × 10⁶ kg

GIVEN

Weight of the Ship = 5 × 10⁵ N

TO FIND

what will be the weight of water displaced bt the ship?

SOLUTION

We can simply solve the above problem as follows;

According to Archimedes principle;

Wᶠ = Wᵈ

Where,

Wᶠ = Weight of floating object.

Wᵈ = Weight of water displaced by the object.

Weight of floating ship = 9.8 ×weight of the ship

= 9.8× 5 × 10⁵

= 4.9 × 10⁶ Kg

Therefore,

Wᵈ = Wᶠ = 4.9 × 10⁶ kg

Hence, The answer is 4.9 × 10⁶ kg

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