Math, asked by jaydeepchauhan3692, 5 hours ago

if a function f is defined as f: Z->Z, f(x)=x²-3 then find the range of the function​

Answers

Answered by mathdude500
2

\large\underline{\sf{Solution-}}

Given that

\rm :\longmapsto\:f : Z \:  \to \: Z \: given \: by \: f(x) =  {x}^{2} - 3

Range of f(x)

\rm :\longmapsto\:Let \: y \:  =  \:  {x}^{2} - 3

\rm :\longmapsto\: {x}^{2}  = y +  3

\rm :\longmapsto\:x =  \sqrt{y + 3}

\rm :\implies\:x \: is \: defined \: if \: y + 3 \geqslant 0

\rm :\implies\:y \geqslant  - 3

\bf\implies \:y \:  \in \: [- 3, \:  \infty )

\rm :\longmapsto\:As \: y \:  \in \: Z

\bf\implies \:y \:  =  \:  \{ - 3, - 2, - 1,0, 1,... \}

Basic Concept Used :-

Range :-

To find the range of f(x)

Step : - 1. Let y = f(x)

Step :- 2. Express x in terms of y, say x = g(y).

Step :- 3. Find the domain of g(y).

Step :- 4. This will be the range of f(x).

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