If a function i homogenous is it inverse homogenous also
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Yes it does automatically imply that f−1(αx)=αf−1(x). We can proceed as follows. Taking the inverse of both side of the original equation gives:
f−1(f(αx))=f−1(αf(x))
This evaluates to
αx=f−1(αf(x))
Now if we define y=f(x), then x=f−1(y) and
αf−1(y)=f−1(αy)
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