Question

if a gas absorbs 200 joule of heat and expands by 500 cm cube against a constant pressure of 2 into 10 raise to 5 Newton per metre then change in internal energy is

Answer 1

Work done = -P∆V = -2*10^5 * (500*10^-6) =
= -1000 * 10^-1 = -100 Joules

So,
Change in Internal energy = ∆Work + ∆Heat (∆Q)

Now,
Gas absorbs 200 Joules and Does work itself of 100 Joules

So,
Change in Internal energy = 200 J - 100 J = 100 Joules