: If a gas in a closed container is pressurized from 15.0 atmospheres to 16.0 atmospheres and its original temperature was 25.0 °C, what would the final temperature of the gas be in degrees Celsius?
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Answered by
9
Answer:
317.867K
Explanation:
Gay-Lussac's Law deals with pressure and temperature.
P1/T1=P2/T2
If we rearrange and get T2 by itself, we get
T2=P2T1/P1
Since temperature needs to be in Kelvin for all gas law calculations,
T1= 298. That gives us the following
T2=16⋅298/15
That answer = 317.866666666666667
Answered by
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Answer:
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