Question

if a gas is compressed to half its volume first rapidly and then slowly, in which case the work done will be greater? ​

Answer 1

Answer:

As long as the force given remains constant, work done is the same since

Work done = Force x displacement

It does not depend on time

But for power, first case is the greater one

Hope it helps :)

Answer 2

Work done is greater for rapid compression because for the same change in volume, increase in pressure greater