Question

If A gets 30% marks more than B, then B gets how much less percent marks than A ?​

Answer 1

Answer:

b gets 30 % less marks then a

Answer 2

Let the marks of B be x

A be x+30% of x

According to question:-

x+30x/100

=130 x/100

=13x/10

Difference=13x/10-x

=3/10

If A marks is x then B's marks

$= \frac{3}{10} \div \frac{13}{10} \times 100$

$= \frac{3}{10} \times \frac{10}{13} \times 100$

$= \frac{300}{13}$

$= 23 \frac{1}{13} \: \: percent$