Question

If a girl cycles at 10 kmph, then she arrives at a certain place at 1 p.m. If she cycles at 15 kmph, she will arrive at the same place at 11 a.m. At what speed must she cycle to get there at noon?

Answer 1

$\huge{Hey Mate!!!}$

☆☞ Here is ur answer ☜☆

✔✔ The distance is constant in this case.

Let the time taken for travel with a speed of 10 kmph be 't'.

Now the speed of 15 kmph is 3/2 times the speed of 10 kmph.

Therefore, time taken with the speed of 15 kmph will be 2t/3 (speed is inversely proportional to time)

Extra time taken = t - 2t/3 = t/3

=> 1pm - 11am = 2hrs

=> t/3 = 2h

=> t = 6 hrs.

Now, Distance = speed x time = 10 x 6 = 60 kms

Time he takes to reach at noon = 6 - 1 = 5 hrs

Now, Speed = 60/5 = 12 kmph.


HOPE IT HELPS!

Answer 2

Extra time taken = t - 2t/3 = t/3

:-1pm - 11am = 2hrs

:-t/3 = 2h

;- t = 6 hrs.

Distance = speed x time

 = 10 x 6

= 60 kms

Time he takes to reach
= 6 - 1

= 5 hrs

Speed = 60/5 = 12 kmph.

thanks me Later ❤️