if a gold ring with a mass of 5.5g changes it's temperature from 25°C to 28°C.how much heat is absorbed by the ring.
Answers
Explanation:
If a gold ring with a mass of 5.50 g changes in temperature from 25.0 to 28.0 degree c, how much heat has it absorbed (C = 0.129 J g^-1 K^-1) Briefly define heat capacity. C and specific heat capacity, C_s Calculate the standard enthalpy of formation of acetylene (C_2H_2) from its elements: 2 C(graphite) + H_2(g) rightarrow C_2H_2 (g) The equations for each step and the corresponding enthalpy changes are: C (graphite) + O_2(g) rightarrow CO_2 (g) delta H^o _rxn = 393.5 kJ/mol H_2(g) + 1/2 O_2(g) rightarrow H_2O(l) delta H^o _rxn = 285.8 kJ/mol 2 C_2H_2(g) + 5 O_2(g) rightarrow 4 CO_2(g) + 2 H_2O(l) delta H^o _rxn = 2598.8 kJ/mol The thermite reaction involves aluminum and iron(II) oxide 2Al(s) + Fe_2O_3(s) rightarrow Al_2O_3(s) + 2 Fe(l) This reaction is highly exothermic and the liquid iron formed is used to weld metals. Calculate the heat released in kilojoules per gram of Al reacted with Fe_2O_3. The delta H for Fe(l) is 12.40 kJ/mol. Given: deltaH^0_f for Fe_2O_3(s) = 822.2 kJ/mol delta H^0 _t for Al_2O_3(s) = -1669.8 kJ/mol