Question

If A got 20 percent more marks than B than by what percent foB are less than the marks of A .

Answer 1

Let B got =x marks

A got 20 % more.

A marks=x+(x×20%)

=x+x/5

=5x+x/5

=6x/5

A got=6x/5

A got How many marks more than B

=6x/5-x

=x/5

Difference=x/5

A=6x/5

$\% = \frac{difference}{a \: marks} \times 100 \\ \\ \frac{ \frac{x}{5} }{ \frac{6x}{5} } \times 100 \\ \\ = \frac{x}{5} \times \frac{5}{6x} \times 100 \\ \\ = \frac{50}{3} \%$

$\boxed{\mathbf{Percent\implies\frac{50}{3}\%}}$