If a graph is plotted between t square and r cube for a planet then its slope will be.???????
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Kepler's Third Law relates the period of an orbit to the radius of an orbit, if the orbit is circular, and to the semimajor axis if the orbit is elliptical. Let's derive it for a circular orbit, assuming a mass m is orbiting a mass M, with r being the radius of the orbit.
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Time period of revolution of planet,
T=v2πr=rGMs2πr=GMs2πr3/2
where Ms is the mass of the sun Squaring both sides, we get
T2=GMs4π2r3
The graph between T2 and r3 is a straight line whose slope is GMs4π2
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