`If a> 0 and a≠1 then the value of 2 sinB can be [(a) +(1/a) ] ?
Answers
Step-by-step explanation:
Enroll For Free

0
Home
»
Study Material
»
IIT JEE Mathematics
»
Trigonometry
»
Trigonometric Identities and Equation
»
TRIGONOMETRIC EQUATIONS
TRIGONOMETRIC EQUATIONS
An equation involving one or more trigonometrical ratios of unknown angle is called a trigonometric equation e.g. cos2 x – 4 sin x = 1
It is to be noted that a trigonometrical identity is satisfied for every value of the unknown angle where as trigonometric equation is satisfied only for some values (finite or infinite) of unknown angle.
e.g. sec2 x – tan2 x = 1 is a trigonometrical identity as it is satisfied for every value of x Î R.
SOLUTION OF A TRIGONOMETRIC EQUATION
A value of the unknown angle which satisfies the given equation is called a solution of the equation e.g. sin q = ½ Þq = p/6 .
General Solution
Since trigonometrical functions are periodic functions, solutions of trigonometric equations can be generalized with the help of the periodicity of the trigonometrical functions. The solution consisting of all possible solutions of a trigonometric equation is called its general solution.
We use the following formulae for solving the trigonometric equations:
· sin q = 0 Þ q = np,
· cos q = 0 Þq = (2n + 1),
· tan q = 0 Þ q = np,
· sin q = sin a Þq = np + (–1)na, where aÎ [–p/2, p/2]
· cos q = cos aÞq = 2np ± a, where aÎ [ 0, p]
· tan q = tan a Þ q = np + a, where aÎ ( –p/2, p/2)
· sin2 q = sin2 a , cos2 q = cos2 a, tan2q = tan2 aÞq = np±a,
· sin q = 1 Þq = (4n + 1),
· cos q = 1 Þ q = 2np ,
· cos q = –1 Þ q = (2n + 1)p,
· sin q = sin a and cos q = cos aÞ q = 2np + a.
here is ur Answer
Now,please mark me as brainlist