Question

if a > 0 then the minimum value of ax^2+bx+c at x= -b/2a is​

Answer 1

Answer:

◦•●◉✿Let f(x)=ax

2

+bx+4

On differentiating w.r.t. x, we get

f

′

(x)=2ax+b

For minimum, put f

′

(x)=0

⇒x=−

2a

b

Since, it is given that at x=1, minimum value is −1

∴1=−

2a

b

⇒2a+b=0 ...(i)

and f(1)=a+b+4=−1

⇒a+b+5=0 ...(ii)

On solving Eq. (i) and (ii) we get a=5,b=−10✿◉●•◦

Answer 2

Answer:

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