Question

) If a > b, then according to addition properties of inequalities a + c a) > a + b b) < a + b c) = a + b d) None of these

Answer 1

ANSWER

Consider the problem

a×b=c×d−−−−(1)a×c=b×d−−−−(2)

Subtracting (2) from (1)

(a×b)−(a×c)=(c×d)−(b×d)

a×(b−c)=(c−b)×d

a×(b−c)−(c−b)×d=0

a×(b−c)+(b−c)×d=0

a×(b−c)−d×(b−c)=0

(a−d)×(b−c)=0

Hence, (a−d) is perpendicular to (b−c)