) If a > b, then according to addition properties of inequalities a + c a) > a + b b) < a + b c) = a + b d) None of these
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Consider the problem
a×b=c×d−−−−(1)a×c=b×d−−−−(2)
Subtracting (2) from (1)
(a×b)−(a×c)=(c×d)−(b×d)
a×(b−c)=(c−b)×d
a×(b−c)−(c−b)×d=0
a×(b−c)+(b−c)×d=0
a×(b−c)−d×(b−c)=0
(a−d)×(b−c)=0
Hence, (a−d) is perpendicular to (b−c)
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