if a>c show that abc - cba = 99(a-c)
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"If a>c
Let’s take 99(a-c) = 6mn
Instead of 99(a-c) substitute 6mn in the equation abc - cba = 99(a-c)
100a+10b+c - (100c+10b+a) = 6mn
Multiples of 99 are 99,198,297,396,495,594,693
So 6mn = 693
Were m+n = 12.
Therefore, abc - cba = 99(a-c)
Hence proved. If a>c show that abc - cba = 99(a-c)
"
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