if a>c show that abc-cba=99(a-c)
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Given, a > c To show : abc – cba = 99(a – c) Proof: abc = 100a + 10b + c ……….(i) (By using property 3) cba = 100c + 10b + a ………..(ii) (By using property 3) Subtracting, equation (ii) from (i), we get abc – cba = 100a + c – 100c – a abc – cba = 99a – 99c abc – cba = 99(a – c) Hence proved.Read more on Sarthaks.com - https://www.sarthaks.com/158701/if-a-c-show-that-abc-cba-99-a-c
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Answer:
Given, a > c To show : abc – cba = 99(a – c)
Proof: abc = 100a + 10b + c ……….(i)
(By using property
3) cba = 100c + 10b + a ………..(ii)
(By using property
3) Subtracting, equation (ii) from (i), we get
abc – cba = 100a + c – 100c – a abc – cba
= 99a – 99c abc – cba = 99(a – c) Hence proved.
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