if a>c show that abc-cba = 99(a-c)
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Hey mate here's the answer:-
Given, a > c To show : abc – cba = 99(a – c) Proof: abc = 100a + 10b + c ……….(i) (By using property 3) cba = 100c + 10b + a ………..(ii) (By using property 3) Subtracting, equation (ii) from (i), we get abc – cba = 100a + c – 100c – a abc – cba = 99a – 99c abc – cba = 99(a – c) Hence proved.
Hope it helps.......
Given, a > c To show : abc – cba = 99(a – c) Proof: abc = 100a + 10b + c ……….(i) (By using property 3) cba = 100c + 10b + a ………..(ii) (By using property 3) Subtracting, equation (ii) from (i), we get abc – cba = 100a + c – 100c – a abc – cba = 99a – 99c abc – cba = 99(a – c) Hence proved.
Hope it helps.......
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