Question

If a gun of mass 15kg fires a buller of mass 5g with a velocity of 30 m/s. The recoil velocity of gun is ...
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Answer 1

Answer:

Let the bullet be = A

and Let the gun be = B

Part A :

mA = 5g

     =0.005 kg

uA = 0

vA = 30 m/s

Part B :

mB = 15 kg

uB = 0

vB = ?

Final :

mA x uA + mB x uB=mA x vA + mB x vB                                      (Formula)

=   0.005 x 0 + 15 x 0 = 0.005 x 30 + 15 x vB

=       0 + 0 = 0.15 + 15 x vB

=         0 = 0.15 + 15 x vB

=            15 x vB + 0.15 = 0

=                 15 x vB = 0 - 0.15

=                     15 x vB = -0.15

=                          vB = -0.15 / 15

=                              vB = -0.1

Recoil velocity of the gun = -0.1 m/s

Recoil Velocity of the gun is 0.1 m/s in the opposite direction

Explanation:

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Answer 2

Answer:

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