if a has some pens and b has some pens if a gives 1 pen to b , they both are equal and if b gives 1 pen to a ,a becomes dubble of b
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Let a have x pen
b have y
x - 1 = y + 1
x - y = 1 + 1
x - y = 2 ...... ( i )
2 ( y - 1 ) = x
2y - 2 = x ... ( ii )
Putting value of x from ( ii ) in ( i )
x - y = 2
2y - 2 - y = 2
y - 2 = 2
y = 4
Putting it in ii
2y - 2 = x
8 - 2 = x
6 = x
A have 6 pens
B have 4 pens.
b have y
x - 1 = y + 1
x - y = 1 + 1
x - y = 2 ...... ( i )
2 ( y - 1 ) = x
2y - 2 = x ... ( ii )
Putting value of x from ( ii ) in ( i )
x - y = 2
2y - 2 - y = 2
y - 2 = 2
y = 4
Putting it in ii
2y - 2 = x
8 - 2 = x
6 = x
A have 6 pens
B have 4 pens.
akashpatelyo2:
Wrong answer
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