if a has to write 810 pages and b has to write 900 pages in a given time. A completes his task 3 days ahead of time and B completes his task 6 days ahead of time. If B wrote 21 pages extra each day during his work, then find out how many pages extra A has to write.
Plz provide detailed explanation
Answers
Answered by
0
Answer:
I also don't know
Step-by-step explanation:
- I aslo don't know
Answered by
0
Answer:
54
Step-by-step explanation:
let the given days be x
so , A finish the 810 pages in (x-3) days
B finish the 900 pages in (x-6) days
one day work of
A= 810/(x-3)
B=900/(x-6)
B-A=21 pages (given)
900/(x-6) - 810/(x-3) =21
0n solving above equation we get
solving for x
we get x=18,-4.7 (neglecting negative value as no. of days can't be -ve)
so x=18
no. of days taken by A =18 - 3
= 15
per day work of A = 810/15
= 54
no. of days taken by B =18 - 6
= 12
per day work of B = 810/12
= 75
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