Chemistry, asked by Happymooder, 10 months ago

If a heat engine absorbs heat at 600°K and rejects heat at 200°K its efficiency is
a) 33%
b) 50%
c) 67%
d) 80%​

Answers

Answered by shaurya1401
4

Answer:

c is the correct answer 67%

Answered by Qwparis
0

The correct answer is option C.

Given: Heat absorbed by heat engine = 600 K.

Heat rejected by heat engine = 200 K.

To Find: Efficiency of engine.

Solution:

Percentage of efficiency of engine = \frac{Q_{1} -Q_{2} }{Q_{1} }*100

Here, Q_{1} =600 K and Q_{2} =400K.

Efficiency = \frac{600-200}{600}*100

= \frac{400}{600}*100

= \frac{2}{3}*100

= 67%

Hence, the efficiency of engine. is 67%.

#SPJ5

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