if a heater with power 1000w gives 4200000j of heat energy in one hour,what will be the temperature raised in the 20 kg of water with temperature 30° c by that heat
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Answer:
Temperature raised=50°C resulting in final temperature of 80°C
Explanation:
Specific heat of water is 4200J/kg meaning it takes 4200 J of energy to raise 1 kg of water by 1°C
Applying 4,200,000 J for 20 kgs, the resulting increase on temperature is 4,200,000/(20*4200) = 50°C
Please correct me if I'm wrong. Cheers !! :)
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