if a helium balloon containing 12m³ of gas at a pressure of 120kPa is released into the air. Assuming that the temperature is constant, calculate the volume the balloon would have when the pressure inside the balloon has fallen to 40kPa. Answer in m³.
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Answer:
36m3
Explanation:
As per gas laws at a constant temperature the product of volume and pressure are directly proportional hence expressed as p1v1=p2v2 where p is pressure while v represent volume.
Subscripts 1 and 2 represent the initial and respectively.Making V2 the subject then
v2=(p1×v1)÷p2
Substituting 120 kpa for p1,12m3 for v1
and 40 kpa for p2 then
therefore,V2 -(120×12)÷40=36m3
therefore bthe volume will be 36 m3
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