Question

if a house has two 60 W bulbs lighted for 5 hrs, a 100W lamp lighted for 2hrs,a 50W TV running for 8hrs and two electric fans working for 10hrs of power of 50W . Then, how many electric units are consumed each day ?​

Answer 1

Answer:

Energy = Power*time

Energy consumed by 100 W bulb per day = 2∗100 Wh

= 0.2 kWh

Energy consumed by 40 W bulbs per day = 4∗40∗4 Wh

= 0.64 kWh

Total energy consumed per day = 0.2 + 0.64 kWh

= 0.84 kWh

Therefore, the energy consumed in 30 days = 30∗0.84 kWh

= 25.2 kWh

Answer 2

Energy and power

Number of 60 W bulb lighted for 5 hours a day $= 2$

Number of 100W lamp lighted for 2 hours a day $=1$

Number of 50 W TV running for 8 hours a day $= 1$

Number of 50 W electric fans works 10 hours  a day $= 2$

We know that,

$Energy= Power\times Time$

Electric energy consumed by bulb $=2\times 60\times 5=600 Wh=0.6 \ KWh$

Electric energy consumed by lamp $= 100\times 2=200 Wh=0.2 \ KWh$

Electric energy consumed by T.V. $= 50\times 8=400 Wh=0.4 \ KWh$

Electric energy consumed by electric fans $=2\times 50\times 10=1000 Wh=1 \ KWh$

Hence total energy consumed by all appliances in a day $=(0.6+0.2+0.4+1)\ KWh=2.2\ KWh$

Hence 2.2 units of electricity is consumed each day.