If a human heart beats once in every 0.8 s, then
find the number of times the heart would have
beaten in the life of a 20 year old person
(1) 7.8 × 108
(2) 4.1 × 1011
(3) 1.32 × 1012 (4) 3.2 × 10
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IN 1 HOUR HOW MUCH SECOND = 60*60
=3600
AND IN 1 DAY=3600*24
=8640
SO IN 365 DAYS(1 YEARS)=8640*365
=3153600
AND IN 20 YEARS NUMBER OF DAY=365*20
=7300(CONSIDER NO LEAD YEAR)
SECOND IN 7300 DAYS IS=7300*3153600
=23021280000 SECONDS
IN 0.8 SEC=23021280000 /0.8
==>28776600000
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