Question

If a hypotenuse of a right angle triangle is 17 cm and base is 15 cm.Find its altitude​

Answer 1

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By using Pythagoras theorem ;

(Altitude )^2 = (hypotenuse )^2-.

(base)^2

=(17)^2-(15)^2

= 289 - 225

= 64

Altitude = √64 = 8 cm

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Answer 2

GIVEN

Hypotenuse=>17cm

Base=>15cm

Altitude=> ?

SOLUTION.

$\fcolorbox{pink}{orange}{by \: pythagores \: theorm}$

${h}^{2} = {b}^{2} + {p}^{2} \\ \\ {(17)}^{2} = {(15)}^{2} + {(p)}^{2} \\ \\ 289 = 225 + {(p)}^{2} \\ \\ 289 - 225 = {(p)}^{2} \\ \\ 64 = {(p)}^{2} \\ \\ p = \sqrt{64 } \\ \\ \color{hotpink} \boxed{p = > 8}$

Note

P= perpendicular or also called altitude.

H= hypontuse

B=Base

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