If A = i^ +j^ and B = 2i^ + 3j^ then unit vector along A+B is :
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Answer:the component of the vector A along B geometrically is :
Bcos (theta)=(A.B÷/B/). (Bcap)
=5/(2)1/2 (i+j)
Explanation:
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Answer:
A + B = i ^+ j^ + 2i^ + 3j^
= i^ +2i^ + j^ + 3j^
= 3i^ +4j^
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