If a = i + j+, b = 2î +2j + 2k, and c = 3 +3; +3k then a+b+c=
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8
Given, a=2i+2j+3k,b=−1+2j+k and c=3i+j
We need to find value of a+tb⊥c
⇒(a+tb)⋅c=0
⇒a⋅c+tb⋅c=0
⇒t=−
b⋅c
a⋅c
⇒t=−
(−i+2j+k)⋅(3i+j)
(2i+2j+3k)⋅(3i+j)
⇒t=−
−3+2+0
6+2+0
=8
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