Question

If(a+ib) = 1 , then prove that
${a}^{2} + {b}^{2} = 1$
​

Answer 1

Answer:

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Answer 2

Answer :

Soulution is provided in the attachment .

Step-by-step explanation:

It's a question of complex number , in the form of (a+ib).

To prove the given Question, first of all we have to square the both sides.

That will come according to identity

${(a + b)}^{2} = 2ab$

The term ${i}^{2} = -1$ in complex number.

So putting this we we will get further expression.

Again taking the complex term in RHS and squaring, we get terms of degree 4 and accordingly.

Now replace the terms from equation (i) .

The terms will finally be equal to given condition which is further equals to 1.

Hence, Proved