If a + ib = c + id A)a^2+c^2=0
B)b^2+c^2= 0
C)b^2+d^2= 0
D)a^2+b^2= c^2+d^2
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Answer:
d]a^2+b^2= c^2+d^2
Step-by-step explanation:
a2+c2=0
b2+c2=0
b2+d2=0
a2+b2=c2+d2
Answer :
D
Solution :
Given that, a+ib=c+id
⇒|a+ib|=|c+id|
⇒a2+b2−−−−−−√=c2+d2−−−−−−√
On squaring both sides, we get
a2+b2=c2+d2
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