Question

if a-ib=c-id, then
a)a^2+c^2=0
b)b^2+c^2=0
c)b^2+d^2=0
d)a^2+b^2=c^2+d^2
ans plz.​

Answer 1

Step-by-step explanation:

So it's a complex number right..?

$a - ib = c - id \\ \\ from \: here \: we \: can \: say.. \\ \\ a = c \: \: and \: \: b = d \\ \\ so \\ \\ {a}^{2} = {c}^{2} \: \: and \: \: {b}^{2} = {d}^{2} \\ \\ {a}^{2} - {c}^{2} = 0 \\ \\ {b}^{2} - {d}^{2} = 0 \\ \\ {a}^{2} - {c}^{2} = 0 = {b}^{2} - {d}^{2} \\ \\ {a}^{2} + {d}^{2} = {b}^{2} + {c}^{2} = 0$

So option b) is correct

Answer 2

Step-by-step explanation:

id - 8253381513

password-9999