Question

If a income is 10% less than that of B by what percent is B income more than a

Answer 1

Hi,

Here's ur answer :-

Let B's income be x

A's income = x - 10% of x = x- x/10 = 9x/10

The question asks by what percent the income of B is more than that of A.

So,Let's say it is by y%

=>9x/10 +y% of 9x/10 = x

(In the left hand side of the equation, 9x/10 is taken common)

=> 9x/10( 1+y/100) = x

=>1+y/100 = x multiplied by 10/9x = 10/9

=> y/100 = 10/9-1 = 1/9

=> y = 100/9 = 11 whole 1/9

So, B's income is greater than A's income by 11 whole 1/9 %

HOPE IT HELPS (^_^)

PLEASE MARK BRAINLIEST