if A intersection to B= A in tersection C then it is true that B is equal to C
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Step-by-step explanation:
Let x∈C
Suppose x∈A⇒x∈A∩C
⇒x∈A∩B(∵A∩C=A∩B)
Thus x∈B
Again suppose x∈
/
A⇒x∈C∪A
⇒x∈B∪A⇒x∈B
Hence C⊆B .......(1)
Similarly we can show that B⊆C .....(2)
Commbining (1) and (2) we get B=C
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