if a is 30500 ,Sn is 325000, d is -1500 then find value of n
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Answer:
Step-by-step explanation
Sn = n/2 [a+(n-1)d]
325000= n/2 [30500+(n-1)(-1500)]
650000 = n[30500-1500n+1500]
650000 = n(32000-1500n)
650000 = 32000n - 1500n²
1500n²-32000n + 650000 = 0
500[3n² - 64 + 1300] = 0
3n² - 64 + 1300 =0
Solve this eq
ganesh11481:
but the formula is Sn =n/2(2a+(n-1)d)
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