Question

If a is 6-sqrt35, find the value of a^2 + 1/a^2​

Answer 1

Answer:

,

Step-by-step explanation:

This is the answer to your question

Answer 2

a=6-_/35

1/a=1/(6-_/35)

=(6+_/35)(6^2-35)

=6+_/35

(rationalised the denominator)

So,

a^2+1/a^2=(6-_/35)^2(6+_/35)^2

=36+35-12_/35 +36+35+12_/35

=71+71

=142...

this is your answer ✔️